Answer:
The ball reaches a height of 29.25 ft after 1.125 seconds
Step-by-step explanation:
The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.
-b/2a
-(36)/2(-16)
-36/-32
1.125 seconds
Now to find the height, we input that value in for t
h = -16t^2 + 36t + 9
h = -16(1.125)^2 + 26(1.125) + 9
29.25 feet
Answer:
15 minutes
Step-by-step explanation:
First, the motorcycle goes at a speed of 40 km/hr.
The question asks for how long it would take to travel 10 km.
Well, there are 60 minutes in an hour, since we will be translating into minutes.
Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.
1/4 of 60 minutes is 15 minutes. So it takes 15 minutes for the motorcycle to travel 10 km.
Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.

Now cross multiply:

Divide both sides by 40:

Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.
Compounded depreciation formula:
A = P(1 - r)ⁿ , where P = original price, r= rate of depreciation, n = number of years and A = actual value (after depreciation):
A= $8000(1 - 11%)⁵ = 8000(0.89)⁵ = 4,467.24 ≈$4,467
Answer:
x = -180
Step-by-step explanation:
0 = 0.65x + 117
-117 = 65x/100
cross-multiply to solve for 'x':
65x = -11700
x = -11700/65
x = -180
The common difference if there is one is the constant difference that occurs between any term and the term before it.... in this case:
There is no common difference,
dx=18,20,16,18 the difference or velocity is not constant...
d2x=2, -4,2 the acceleration is not constant...
d3x=-6,6 the thrust is not constant
Now we might be tempted to say that:
d4x=12 and say that that is constant and we COULD make a quartic equation fit all the data points, but without further data points in the sequence there is no mathematical proof that the quartic equation would produce accurate data points outside of the range given...
And solving a system of five equations for five unknowns is tedious for such a problem...a^4+bx^3+cx^2+dx+e=y