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Alex
3 years ago
9

What is the solution to the system of equations y= -3x+6 y=9

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

<h2>C. (-1, 9)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}y=-3x+6\\y=9\end{array}\right\ \text{put the value of}\ y\ \text{to the first equation}\\\\9=-3x+6\qquad\text{subtract 6 from both sides}\\3=-3x\qquad\text{divide both sides by (-3)}\\-1=x\to x=-1

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n= -2

Step-by-step explanation:

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Billy invests $5,000 in an account at 4.2% for 15 years, compounded monthly. Assuming no other deposits or withdrawals are made,
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5,008 and you can find it on nerd wallet
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2 years ago
What is the rational number equivalent to 1.28? The 1.28 has a line above the 28
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<span>the line over the 28 means the 28 repeats forever.
1.282828.... and so on
 let x be the rational number 1.28...
we can use this trick:
100*1.282828....= 128.282828...
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3.89×10^9 in standard form​
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7 0
3 years ago
A report by the US Geological Survey indicates that glaciers in Glacier National Park, Montana, are shrinking. Recent estimates
postnew [5]

Answer

a) C

b) B

c) C, E

d) 15.5

e) 0.7

f) 67.7

Step-by-step explanation

a) A linear equation can be written as y=mx+c where m is the slope and c is the intercept on the y-axis. The slope describes how y changes when x changes. A negative value means the it is a decreasing change. In our case, y is A and x is t. Thus, the slope of the equation is m=-0.062. This means that the area of glacier is decreasing by 0.062 \text{km}{}^2 = 62000 \text{m}{}^2 every year since 2000.

b) The A-intercept (= 16.2 \text{km}{}^2) represents the area covered when t=0. But t=0 starting from year 2000. This intercept then represents the area covered by glacier in the year 2000. Therefore, the area covered by glacier in 2000 was 16.2 \text{km}{}^2.

c) A=f(t) means the area covered after year 2000. Setting it to 12 means the area covered after t years is 12 \text{km}{}^2). t is therefore the number of years since 2000 that the total area covered will be 12 \text{km}{}^2).

d) f(12)=16.2−0.062\times12 =16.2-0.744 = =15.456 15.5 \text{km}{}^2 to 1 decimal place.

e) The term involving t represents the disappearing area. In 12 years, the disappeared area is 0.062\times12=0.744 =0.7 \text{km}{}^2 to 1 decimal place.

f) f(t)=16.2−0.062t =12

0.062t = 16.2-12 = 4.2

t = \dfrac{4.2}{0.062}=67.7419\ldots =67.7 years to 1 decimal place.

8 0
3 years ago
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