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blagie [28]
3 years ago
14

A cell phone company charges a monthly fee plus $0.25 for each Text message. The monthly fee is $30.00 and you owe $59.50. How m

any Tex messages did you have?
Mathematics
1 answer:
Travka [436]3 years ago
5 0
They charge $30 per month as a base so that is y
They also charge $0.25 per text message, this is x

so $0.25x+$30y=$59.50
first subtract 30 from both sides to get x alone
$0.25x=$29.50
To find amount of text messages sent, we have to divide
$29.50/$.25
29.50/.25=118
This person sent 118 text messages
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Mike has a total of 25 dimes and nickels. If the total value of the coins is $1.90 how many of each coin does he have? ​
bezimeni [28]

Answer:

12 nickels and 13 dimes

Step-by-step explanation:

d = # of dimes

n = # of nickels

Set up a System of Equations as follows:

d + n = 25

.10d + .05n = 1.90

now solve for 'd' or 'n' and use Substitution:

d = 25-n

.10(25-n) + .05n = 1.90

2.5 - .10n + .05n = 1.90

-.10n + .05n = -0.6

-.05n = -0.6

n = -0.6/-.05

n = 12

d + 12 = 25

d = 13

Check:   12(.05) + 13(.10) should equal 1.90

0.60 + 1.30 = 1.90

1.90 = 1.90

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3 years ago
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How do I get X for this question?​
exis [7]

Answer:

The value of x is 12

Step-by-step explanation:

To find the value of x, we need to note that the interior angles are equal to 180. We also know that angle R is equal to 180 - (8 + 6x). So we can add all of this together and set equal to 180.

180 - (8 + 6x) + 4x + 2 + 30 = 180

180 - 8 - 6x + 4x + 2 + 30 = 180

-2x + 24 = 0

-2x = -24

x = 12

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3 years ago
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Answer:

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EastWind [94]

Answer:

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Step-by-step explanation:

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2 years ago
Given triangle DEF similar to triangle GHF. Enter segments in the blanks provided that would result in a true equation.
Paul [167]

Given:

The triangles DEF is similar to GHF.

The objective is to find a similar ratio of DF/DE.

Explanation:

Using the basic proportionality theorem, for the similar triangles DEF and GHF,

\frac{DE}{GH}=\frac{DF}{GF}=\frac{EF}{HF}\text{ . . . .   ..  .(1)}

Considering the first two ratios of equation (1),

\frac{DE}{GH}=\frac{DF}{GF}

On interchanging the segments further,

\frac{DF}{DE}=\frac{GF}{GH}

Hence, the required segment in the blanks is GF/GH.

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