The average decrease in value can be solve by first solving the value at year 1 and year 2
and i think the equation is <span>f(x)=10,000(0.73)^x</span>
at x = 1
<span>f(x) = 10,000(0.73)^x
</span><span>f(1) = 10,000(0.73)^(1)
f(1) = 7300
at x = 2
</span><span>f(x) = 10,000(0.73)^x
</span><span>f(2) = 10,000(0.73)^(2)
f(2) = 5329
so the average decrease = ( 7300 - 5329) = $ 1971 per year</span><span>
</span>
1350 (dont take my word for it, but i belive this is right)
You take 10/60 and multiply it by 100
10/60=0.1667
0.1667*100= 16.67%
Answer: 2 feets
Step-by-step explanation:
Recommended density = 7 fish/ ft^3
If recommended density guideline is followed:
Number of fishes in aquarium = 42
Length of aquarium = 3ft
Width = 1ft
Height =?
Volume of aquarium = Length × width × height
Volume = 3 × 1 × h = (3ft^2 × h)
Therefore ;
If
1ft^3 = 7 fishes
x ft^3 = 42 fishes
Cross multiply
7(x)ft^3 = 42 fishes
x ft^3 = (42÷7)
x ft^3 = 6
Therefore volume of the aquarium with 42 fishes is 6ft^3
Volume = (3ft^2 × h)
6ft^3 = 3ft^2 × h
h = (6ft^3) / (3ft^2)
h = 2ft
Answer:
i think 17
Step-by-step explanation:
