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Alekssandra [29.7K]
3 years ago
6

What do you mean by mean (average)?collect the age of 8friends and calculate their average ages. ​

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

its basically the average

Step-by-step explanation:

To find it,add up all the numbers and then the answer that you get,you divide it by the amount of numbers you added up...

Hopefully this helped

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Integrala x la a treia ori ln la a doua dx va rog
Studentka2010 [4]

I don't speak Romanian, but the closest translation for this suggests you're trying to compute

\displaystyle \int x^3 \ln(x)^2 \, dx

Integrate by parts:

\displaystyle \int x^3 \ln(x)^2 \, dx = uv - \int v \, du

where

u = ln(x)²   ⇒   du = 2 ln(x)/x dx

dv = x³ dx   ⇒   v = 1/4 x⁴

\implies \displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac12 \int x^3 \ln(x) \, dx

Integrate by parts again:

\displaystyle \int x^3 \ln(x) \, dx = u'v' - \int v' du'

where

u' = ln(x)   ⇒   du' = dx/x

dv' = x³ dx   ⇒   v' = 1/4 x⁴

\implies \displaystyle \int x^3 \ln(x) \, dx = \frac14 x^4 \ln(x) - \frac14 \int x^3 \, dx

So, we have

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac12 \left(\frac14 x^4 \ln(x) - \frac14 \int x^3 \, dx \right)

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac18 \int x^3 \, dx

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac18 \left(\frac14 x^4\right) + C

\displaystyle \int x^3 \ln(x)^2 \, dx = \frac14 x^4 \ln(x)^2 - \frac18 x^4 \ln(x) + \frac1{32} x^4 + C

\boxed{\displaystyle \int x^3 \ln(x)^2 \, dx = \frac1{32} x^4 \left(8\ln(x)^2 - 4\ln(x) + 1\right) + C}

3 0
2 years ago
25 points for right answers
Free_Kalibri [48]
You divide by 16 so you can get each ingredient per serving then you multiply that by 4 and you get your answer

8 0
2 years ago
Read 2 more answers
Multiply. Write your answer in standard form<br> 3i(-5+i)
ipn [44]
-14i is the answer to the equation
8 0
3 years ago
The number 1.3,1/1/3,1.34 in least to greatest
elixir [45]
1.3, 1 1/3, 1.34

The decimal version of 1 1/3 is 1.333 (so on)

so 1.3 is less than 1.333 and 1.333 is less than 1.34

1.3<1.333<1.34
4 0
3 years ago
Will give brainliest!
ira [324]

Answer:

- 1/4

Step-by-step explanation:

Where you see X, substitute with 1/3

Solve the power/exponent first:

6(1/3) = 2

That is ; - 4(1/4)^2

Solve the parenthesis:

(1/4)^2 = 1/16

-4(1/16)

= - 1/4

8 0
2 years ago
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