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Bond [772]
3 years ago
11

What happens when y = -f(-x)?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

It's a reflection over the x axis.

Step-by-step explanation:

Idk I googled it.

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Svetradugi [14.3K]
Simpler maximum and minimum problems are examples of applications of quadratic function modeling.  Such problems have only one answer:  max OR min.  More complicated problems might have several maxima or minima.

4 0
3 years ago
Plzz help for brianly
shutvik [7]

Answer:

342yd^2

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
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True or False: The amount of time it takes to complete an examination has a left skewed distribution with a mean of 65 minutes a
nekit [7.7K]

Answer:

True

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 65, \sigma = 8, n = 64, s = \frac{8}{\sqrt{64}} = 1

If 64 students were randomly sampled, the probability that the sample mean of the sampled students exceeds 71 minutes is approximately 0.

This probability is 1 subtracted by the pvalue of Z when X = 71. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{71 - 65}{1}

Z = 6

Z = 6 has a pvalue very close to 1.

1 - 1 = 0.

So approximately 0 probability that the sample mean of the sampled students exceeds 71 minutes.

The answer is true.

6 0
3 years ago
Subtract this problem
galina1969 [7]
I think it's 1.90. I am not fully sure about the answer if it's wrong.
6 0
3 years ago
Hurrry i need help nowwwwwwwwwwwwwwwww
Shtirlitz [24]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
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