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3 years ago

Choose two ordered pairs that belong in quadrant two screenshot included

Mathematics

1 answer:

hjlf3 years ago

5 0

Answer:

Answer (B) and (D)

Step-by-step explanation:

First we need to figure out: What is quadrant II about?

As said in the picture provided, quadrant II is in the upper left corner of a graph.

For a point to be in QII, the x values need to be negative, and the y values need to be positive.

B: (-4,2) and D: (-3,5) would belong in QII.

Their x values are negative, and the y values are positive.

Therefore, B and D would be the correct answers.

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What do both the Senate and the House of Representatives require of people running for election?

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To be apart of that state for atleast ten years is one.

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(x-2)=-1/4(x-8) please show steps

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Step-by-step explanation:

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3 years ago

The diameters of ball bearings are distributed normally. The mean diameter is 83 millimeters and the standard deviation is 3 mil

Alenkinab [10]

Answer:

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 83, \sigma = 3$

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.

This is 1 subtracted by the pvalue of Z when X = 85. Then

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{85 - 83}{3}$

$Z = 0.67$

$Z = 0.67$ has a pvalue of 0.7486.

1 - 0.7486 = 0.2514

0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.

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3 years ago

A baby weighed 7.25 lb at birth at the end of 8 months , the baby weighed 2 1/2 times its birth weight. how many pounds did the

d1i1m1o1n [39]

Simply multiply the baby's original weight, which is 7.25 lbs, by 2.5

7.25lbs x 2.5 = 18.125 lbs

The baby weighted 18.125 pounds at the end of 8 months.

Hope this helps and May the Force Be With You!

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Answer:

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