Determine the probability of the event, given the following information. Express as a reduced fraction.

On September 25, 2014 Colson Corp. sold 200,000 widgetrons to Cavanaugh Corp at $5 per unit. Half of the units were delivered on

borishaifa [10]

On September 25.2014 Colson Corp. sold 200.000 widgetrons for 5$ per unit.
200.000*5$=1.000.000$. Same day company was paid for 40% which is 400.000$.
The rest of the money he get paid in two equal parts on November 15.2014 and January 20.2015. So Calson Corp. was paid 300.000$ on November 15.2014 and 300.000$ on January 20.2015.

6 0

3 years ago

A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0

3 years ago

Will mark brainliest and there’s a button for the pic

professor190 [17]

Answer:

There is nothing there

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the inequality- x+18 ≥ 8x+4 or 15x-15 ≤ 15x+5<br><br> I give Brainliest!

r-ruslan [8.4K]

Answer:

x ≥ 2

0 ≤ 20 (not quite sure if the question is right)

Step-by-step explanation:

x+18 ≥ 8x+4

x - 8x ≥ 4 - 18

-7x ≥ -14

x ≥ $\frac{-14}{-7}$

x ≥ 2

________________

15x-15 ≤ 15x+5

15x - 15x ≤ 5 + 15

0 ≤ 20

(I don't think this is the right question...cuz theres a 0)

6 0

2 years ago

2 variable inequalities from their graphs . Please answer. Ty!

Alexus [3.1K]

Answer:

y≤ $\frac{1}{3} x+1$

Step-by-step explanation:

Since the graph is facing down, We know the equation is y<mx+b

Since slope is rise/run the slope is 1/3.

Since the y intercept (The point where the line hits y) is 1, the equation is

y<1/3x+1

BUT WAIT!

The line is solid meaning that we have to include the line as part of the values. This will make the new equation

y≤ $\frac{1}{3} x+1$

8 0

3 years ago