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3 years ago

10

Factorise fully : 4(x - y)^2 - 9(x + y)^2

2 answers:

sergeinik [125]3 years ago

8 0

Answer:

- ( 5x + y ) ( x + 5y )

or

-5x^2 - 5y^2 - 26xy

Archy [21]3 years ago

4 0

Answer:

Step-by-step explanation:

4(x^2-2xy+y^2)-9(x^2+2xy+y^2)

4x^2-8xy+4y^2-9x^2-18xy-9y^2

-5x^2-26xy-5y^2

-5x^2-xy-25xy-5y^2

-x(5x+y)-5y(5x+y)

(-x-5y)(5x+y) or you can also remove the negative one to get

-(x+5y)(5x+y)

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3 years ago

Guys please help me out ASAP, Due today. I

Mice21 [21]

Answer:

$T_7 = 11$

$T_n = 2n- 3$

Step-by-step explanation:

Given

$S_n = n^2 -2n$

$T_n = S_n - S_{n-1}$

Solving (a): T7

Substitute 7 for n in $T_n = S_n - S_{n-1}$

$T_7 = S_7 - S_{7-1}$

$T_7 = S_7 - S_6$

Calculate S7 and S6

$S_n = n^2 -2n$

$S_7 = 7^2 - 2 * 7 = 35$

$S_6 = 6^2 - 2 * 6 = 24$

So:

$T_7 = 35 -24$

$T_7 = 11$

Solving (b): Tn

$T_n = S_n - S_{n-1}$

Where $S_n = n^2 -2n$

Calculate $S_{n-1}$

We have:

$S_{n-1} =(n-1)^2 - 2(n-1)$

Open brackets

$S_{n-1} = n^2 -2n + 1 -2n +2$

$S_{n-1} = n^2 -2n-2n + 1 +2$

$S_{n-1} = n^2 -4n + 3$

So:

$T_n = S_n - S_{n-1}$

$T_n = n^2 - 2n - (n^2 -4n + 3)$

$T_n = n^2 - 2n - n^2 +4n - 3$

Collect Like Terms

$T_n = n^2 - n^2- 2n +4n - 3$

$T_n = 2n- 3$

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4 years ago

Read 2 more answers

The combined weight of three basset hounds is 185 pounds. The two smaller dogs weigh the same. The difference between the larger

olga2289 [7]

Answer:

75 pounds

Step-by-step explanation:

(x) + (x) + (x+20) = 185

3x + 20 = 185

3x = 165

x = 55

Large dog = 55 + 20 = 75

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4 years ago

1. Consistent <br> 2. Equivalent <br> 3. Inconsistent

omeli [17]

Answer:

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7 0

3 years ago