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2 years ago

Sharon drops a rubber ball from a height of 160 feet. Every bounce sends the

Mathematics

1 answer:

spayn [35]2 years ago

7 0

Answer:

140 feet

Step-by-step explanation:

If the first time she dropped the ball was from 160 feet then the second time she dropped the ball is would bounce back up 80 feet. The third time it would bounce 40 feet. And the 4th time it would bounce 20 feet

So the total distance the ball traveled from the first time it hit the ground is 140 feet

I'm not 100% sure I understand the question but I tried

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There are only chickens and pigs in Henry's Barn Henry counted a total of Sixteen animal heads and a total of 50 animal feet.How

raketka [301]

Answer:

9 pigs

Step-by-step explanation:

We have the following numbers of heads:

pigs (p) + chickens (c) = 16 animal heads (1)

And the following numbers of feet:

4p + 2c = 50 animal feet (2)

From equation (1):

p = 16 - c (3)

By entering equation (3) into (2) we have:

4(16 - c) + 2c = 50

64 - 4c + 2c = 50

c = 7

Now, entering the value of c into equation (3) we have the next value of p:

p = 16 - c

p = 16 - 7

p = 9

Therefore, the number of pigs that Henry has is 9.

I hope it helps you!

4 0

2 years ago

Please answer correctly i will give u 10 pts and brainleist ! be first

Jet001 [13]

Answer:

m= 15 b=25

Step-by-step explanation:

the slope is 15 because thta is the unit rate and the missing point that isnt shown is (0,25)

5 0

2 years ago

2. Deshay borrowed $400 from the bank for 1 year. The bank charges 14% interest

Papessa [141]

Answer:

The bank charged 56 dollars in interest

7 0

3 years ago

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

PtichkaEL [24]

Answer:

The correct answer is 9 m per $second^{2}$

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per $second^{2}$

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x m per $second^{2}$ .

∴ 54 = m × x

⇒ x = $\frac{54}{6}$ = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per $second^{2}$ .

6 0

3 years ago

X + 3 - 3=-6 show all work

docker41 [41]

Answer:

x = -6

Step-by-step explanation:

$x+3-3=-6~(Given)\\x=-6~(Combine~like~terms)$

5 0

2 years ago