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Nina [5.8K]
3 years ago
13

What are the first 5 terms of 30-n^2

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

29, 26, 21, 14, 5

Step-by-step explanation:

To find the first 5 terms, substitute n = 1, 2, 3, 4, 5 into the n th term formula.

30 - 1² = 30 - 1 = 29

30 - 2² = 30 - 4 = 26

30 - 3² = 30 - 9 = 21

30 - 4² = 30 - 16 = 14

30 - 5² = 30 - 25 = 5

The first 5 terms are 29, 26, 21, 14, 5

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kari74 [83]

Answer:

x = 1/5 ,  and   x = - 1/5

Step-by-step explanation:

25x² – 1 = 0

5²x² - 1² = 0

(5x - 1)(5x + 1) = 0

5x -1 = 0,  5x + 1 = 0

x = 1/5 ,     x = - 1/5

8 0
3 years ago
Michael bought 0.44 pound of sliced turkey what is the value of the digit in the hundreds place
balandron [24]
4 because on a decimals chart there are no ones so in 0.44 4 is in the hundreds place
   

I hope this helped you

7 0
3 years ago
3 over 5 x 4 over 9​
Gnom [1K]

Answer:

4/15

Step-by-step explanation:

3/5x4/9=

12/45=

4/15

6 0
3 years ago
The student council is having a dinner fund-raiser. The cost to rent the banquet hall for an evening is $185. The cost per plate
dexar [7]

Given

cost to rent the banquet hall for an evening is $185. The cost per plate of food is $3.50. If the tickets to the dinner banquet are $17.50 per person

find out  people must attend in order for the school to earn a profit.

To proof

banquet hall cost =$185

cost per plate of food =$3.50

tickets to the dinner banquet =$17.50

let the number  of people attend the  dinner = x

the equation becomes

17.50x - (3.5x + 185) ≥ 0

now solving the above equation

17.50x - 3.5 x ≥ 185

14x ≥ 185

x ≥ 13.21

x ≥ 14 (approx )

To earn profit 14 people must attend the dinner.

Hence proved





5 0
3 years ago
Plz help!<br> Evaluate the limit of the following.<br> (1/n)(sin(n*pi/2))
photoshop1234 [79]

\frac{\pi}{2}

Step-by-step explanation:

When n->0 ,\frac{Sin(kn)}{n}->k

This is because,

using l'hospital's rule,Lt_{n->0}\frac{sin(kn)}{n}=\frac{kcos(n)}{1} =\frac{k\times 1}{1} =k

In the given question,k=\frac{n\times\pi}{2}

So,the given limit evaluates to \frac{n\pi}{2}

8 0
3 years ago
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