Answer:
Use the appropriate entry method for piecewise functions for the graphing calculator of interest.
Step-by-step explanation:
For Desmos, the entry looks like ...
f(x) = {x ≤ 2: -2x-1,-x+4}
_____
For a TI-84 calculator, the entry may look like ...
Y₁ = (-2X–1)(X≤2) + (-X+4)(X>2)
The symbols ≤ and > come from the TEST menu, which is the (2nd) shift of the MATH key.
Note that the function is the sum of the pieces, each piece multiplied by a test. For something like 0≤x<2, the multiplier would be a pair of tests:
... (0≤X)(X<2)
Answer:
The solution would be (5, -2)
Step-by-step explanation:
To use this method, start by multiplying the second equation by -1. Then add the two equations together.
9x + 5y = 35
-2x - 5y = 0
------------------
7x = 35
x = 5
Now that we have the value of x, use it to solve either equation for y.
2x + 5y = 0
2(5) + 5y = 0
10 + 5y = 0
5y = -10
y = -2
She only has made one full quilt and half of another. So 1.5
We know that
The square root property<span> is one method that is used to find the solutions to a quadratic equation. This method involves taking the square roots of both sides of the equation.
</span>(x – 3)² – 32 = 17-------> (x – 3)² = 17+32-----------> (x – 3)² = 49
(x – 3)² = 7²--------> <span>will take the square root of each side
</span>so
√(x – 3)²=(+-)√7²------> <span>notice the use of the </span> sign (+-), this will give us both a positive and<span> a negative root
</span>
then
x-3=7--------> x=10
x-3=-7-------> x=-4
the answer Part a) is
x=10
x=-4
Part b) Explain why the given equation has two solutions.
the answer part b) is
Because exist<span> the possibility of two roots for every square root, one positive and one negative</span>
Answer:
A
Step-by-step explanation:
bc it's the most simple option for roxanne
