All categories

3 years ago

Which of the following is the product of the rational expressions down below? x-3/x+5•3x/x-5

Mathematics

1 answer:

quester [9]3 years ago

5 0

Answer:

$\dfrac{3x^2-9x}{x^2-5^2}$

Step-by-step explanation:

$\dfrac{x-3}{x+5} \cdot \dfrac{3x}{x-5} = \dfrac{(x-3)\cdot 3x}{(x+5)(x-5)} = \dfrac{3x^2-9x}{x^2-5^2}$

You might be interested in

Show that 2^[x+1]-2^[x-1]= 15 can be written as 2[2^x]-1/2[2^x]= 15

Basile [38]

$~~~~~~2^{x+1} - 2^{x-1} = 15\\\\\implies 2^x \cdot 2^1 - 2^x \cdot 2^{-1}=15~~~~~~~~~~~~~~~~~~;[a^m \times a^n = a^{m+n}]\\\\\implies 2 \left(2^x\right) - \dfrac 12 \left(2^x \right) = 15~~~~~~~~~~~~~~~~~~~~;\left[a^{-n} = \dfrac 1{a^n},~~~a\neq 0 \right]\\\\\text{Showed.}$

7 0

2 years ago

Read 2 more answers

Help me again pls and who ever gets it correct gets 20 points plus brainliest

Ostrovityanka [42]

Answer:just drag across

Step-by-step explanation:

4 0

2 years ago

Who is better math or science

Zielflug [23.3K]

SCIENCE CAUSE MATH HARDDDDDDDDDDDDDDDDDDDDD

4 0

2 years ago

Read 2 more answers

Is this correct help plzz

const2013 [10]

None of the offered choices is correct.

The radical cannot be simplified. If rewritten, it must be written as something like
$x \sqrt[3]{ \frac{6}{x}}$
or
$\frac{6x}{ \sqrt[3]{36x}}$

3 0

3 years ago

A square with an area of A2 is enlarged to a square with an area of 25A2. How was the side of the smaller square changed?

Mamont248 [21]

Answer:

second option : the side length was multiplied by 5.

Step-by-step explanation:

a = side length of the original square

A² = a×a

(a+5)×(a+5) = a² + 10a + 25

and that should be equal to a²×25

a² + 10a + 25 = 25a² ?

10a + 25 = 24a²

no, that is not true for all a

a×5 × a×5 = a²×25 = 25A²

this is the correct solution, as it is true for all a.

5 0

2 years ago

Read 2 more answers