Question

Which number should follow in this series: 64/64 9/12 6/12​

Answer 1

Answer: $\frac{1}{4}$

Step-by-step explanation:

You can reduce the fractions, then:

$\frac{64}{64}=1$

$\frac{9}{12}=\frac{3}{4}$

$\frac{6}{12}=\frac{3}{6}=\frac{1}{2}$

Rewrite them as following:

$1,\frac{3}{4},\frac{1}{2}$

If you subtract the first number and the second number, you obtain:

$1-\frac{3}{4}=\frac{1}{4}$

 If you subtract the second number and the second number, you obtain:

$\frac{3}{4}-\frac{1}{2}=\frac{1}{4}$

Therefore, you must subtract $\frac{1}{2}$ and $\frac{1}{4}$ to obtain the number asked. Then, this is:

$\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Answer 2

Answer:

$\texttt{The number following is }\frac{1}{4}$

Step-by-step explanation:

Series is

         $\frac{64}{64},\frac{9}{12},\frac{6}{12}.....$

Let us simplify

         $\frac{64}{64},\frac{9}{12},\frac{6}{12}.....=1,\frac{3}{4},\frac{1}{2}.....$

So this is arithmetic progression with 1 as first term and $-\frac{1}{4}$ as common difference.

Next term of AP will be $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

$\texttt{The number following is }\frac{1}{4}$