A toy rocket is launched from the top of a building 135 feet tall at an initial velocity of 167 feet per second. Give the functi
1 answer:
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Lagrange multipliers:
(if 
)
(if )
(if 
)
In the first octant, we assume
, so we can ignore the caveats above. Now,
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
.
We also need to check the boundary of the region, i.e. the intersection of
with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force 
, so the point we found is the only extremum.
In the first octant, we assume
so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of
We also need to check the boundary of the region, i.e. the intersection of
Answer:
The value of 4 is an input of the function
Step-by-step explanation:
Let
x -----> the independent variable or input value
y ----> the dependent variable or output value
we know that
Looking at the graph
The domain (input values) of the linear function is equal to the interval
[1,∞)
All real numbers greater than or equal to 1
The range (output values) of the linear function is equal to the interval
(-∞,3]
All real numbers less than or equal to 3
therefore
The value of 4 is an input of the function