A toy rocket is launched from the top of a building 135 feet tall at an initial velocity of 167 feet per second. Give the functi
on that describes the height of the rocket in terms of time t
1 answer:
Answer:
h(t) = = -16t^2 + 167t + 135
Step-by-step explanation:
This is an equation of motion of an object umder a constant acceleration(here it is the acceleration due to gravity);
h(t) = = -16t^2 + 167t + 135.
Note: t is the time in seconds and h is the height in feet at time t.
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