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3 years ago

12

cupcakes are packed 6 to a box. If Abby only buys full boxes of cupcakes, give two possible numbers of cupcakes that she could b

uy.

2 answers:

Mazyrski [523]3 years ago

7 0

Any number that's a multiple of six is acceptable.

nirvana33 [79]3 years ago

4 0

6 or 12 i'm not really sure thats a good question

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Can u break it down and help me answer 13 and 15 thx

olya-2409 [2.1K]

13) The product is a name for the answer to a multiplication question.
6.65*10,000
=66500 (the decimal point moved 4 places to the right (you're multiplying) since they're 4 zeros in 10,00)

15) The quotient is a name for the answer to a division question.
2.374/100
=0.02374 ( the decimal point moved 2 places to the left ( you're dividing) since they're 2 zeros in 100)

Hope this helps! A thanks/brainiest answer would be appreciated :)

3 0

3 years ago

An internal angle of a regular polygon is 160 degrees, how many sides does it have

Softa [21]

They should have 53

3 0

3 years ago

What is the mean absolute deviation of the the following set of data<br> 6 10 8 8

muminat

Answer:

The Mean Absolute Deviation is 1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS PROBLEM AND EXPLAIN HOW YOU GOT THE ANSWER!?!?

Advocard [28]

4:10 pm ....................................

7 0

2 years ago

The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th

Ilia_Sergeevich [38]

Answer:

(0.0757;0.1403)

Step-by-step explanation:

1) Data given and notation

Republicans =115

Democrats=331

Independents=54

Total= n= 115+331+54=500

$\hat p_{ind}=\frac{54}{500}=0.108$

Confidence=0.98=98%

2) Formula to use

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the population proportion is given by this formula

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

We have the proportion of independents calculated

$\hat p_{ind}=\frac{54}{500}=0.108$

We can calculate $\alpha=1-conf=1-0.98=0.02$

And we can find $\alpha/2 =0.02/2=0.01$ , with this value we can find the critical value $z_{\alpha/2}$ using the normal distribution table, excel or a calculator.

On this case $z_{\alpha/2}=2.326$

3) Calculating the interval

And now we can calculate the interval:

$0.108 - 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.0757$

$0.108 + 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.1403$

So the 98% confidence interval for this case would be:

(0.0757;0.1403)

7 0

2 years ago