E. Commutative property of multiplication
Answer: $8.80 for one hour of mowing and $40.50 for 5 hours of babysitting
Step-by-step explanation:
Answer:
Option C is correct.
Step-by-step explanation:
We have been given total 8 data
Data is : 12,15,18,20,23,23,28
Here, n=7
Median is 
Median is 20.
When one data is added n=8
The median of even number of data is

Median is
Median is 
4th terms is 20
5th terms is 23
Since, median should not be change hence,
Median will be 20.
Therefore, option C is correct.
Answer:
0.026
Step-by-step explanation:
Given the result of 10 coin flips :
T,T,H,T,H,T,T,T,H,T
Number of Heads, H = 3
Number of tails, T = 7
Let :
B = biased coin
B' = non-biased coin
E = event
Probability that it is the biased coin:
P(E Given biased coin) / P(E Given biased coin) * P(E Given non-biased coin) * P(non-biased coin)
P(E|B)P(B) / (P(E|B)*P(B) + P(E|B')P(B')
([(0.75^3) * (0.25^7)] * 0.5) /([(0.75^3) * (0.25^7)] * 0.5) + (0.5^10) * 0.5
0.0000128746 / 0.00050115585
= 0.0263671875
Answer:
Specific Learning Outcomes:
Solve problems that involve finding powers of a number
Description of mathematics:
In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.
Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further, these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …
The same is true of the digit in the tens place.