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mariarad [96]
3 years ago
8

A belouga whale is 5 yards and 3 inches long and a gary whale is 15 yards and 5 incheslong

Mathematics
2 answers:
belka [17]3 years ago
8 0

Answer:

10 yards 2 inches

Step-by-step explanation:

15 yd 5 in - 5 yd 3 in =

10 yards and 2 inches

Ira Lisetskai [31]3 years ago
8 0
The answer is 10 yards and 2 inches. Hope it helps
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Sally took her stats test last week and scored a 45%. The class average was 55%with a standard deviation of 4.5. How many standa
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Answer: A

Step-by-step explanation:

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2 years ago
A website manager has noticed that during the evening​ hours, about 5 people per minute check out from their shopping cart and m
Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is​ made

c) 0.05% probability that seven people make a purchase in the next four ​minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that \mu = 5

a) What model might you suggest to model the number of purchases per​ minute? ​

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per​ minute.

b) What is the probability that in any one minute at least one purchase is​ made? ​

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is​ made

c) What is the probability that seven people make a purchase in the next four ​minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

\mu = 4*5 = 20

We have to find P(X = 7).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005

0.05% probability that seven people make a purchase in the next four ​minutes

8 0
3 years ago
The expression “5 factoral” equals:?<br>Answers- <br>125<br>120<br>25<br>10<br>Need help ASAP
VLD [36.1K]

Answer:

120

hope it helps!!

5 0
3 years ago
:
Gnoma [55]

Answer:

a is the answer

Step-by-step explanation:

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3 years ago
How do you solve this equation 2/3b=-12
Airida [17]
2/3b = 12

First you have to get rid of 2/3, so you multiply both sides by its reciprical:
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2 years ago
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