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2 years ago

6 1⁄6 - 3 5⁄12 = plz help me with it

Mathematics

1 answer:

konstantin123 [22]2 years ago

3 0

Answer:

33/12 or 2.75

Step-by-step explanation:

6 1⁄6 - 3 5⁄12

37/6 - 41/12

74/12 - 41/12

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Solve the equation!3 tan^3θ = tan θ

andreev551 [17]

3 tan³ t(theta) = tan t(theta)
3 tan³ t - tan t = 0
tan t ( 3 tan² t - 1 ) = 0
tan t = 0
t 1 = k π , k ∈ Z
3 tan ² t - 1 = 0
3 tan ² t = 1
tan ² t = 1/3
tan t = +/- √3/3
t 2 = π / 6 + k π
t 3 = - π / 6 + k π , k ∈ Z

8 0

3 years ago

What does n equal in 2n+33

lana66690 [7]

N= -16.5

Subtract 33 then divide by 2
2n=-33
n=-33/2 or n=-16.5

4 0

2 years ago

A pizza shop charges $2.00 for a slice that is one-eighth of a pizza and $3.00 for a slice that is one-fourth of a pizza. One da

Lelu [443]

Answer:

Step-by-step explanation:

6x8=48 slices to be sold in 8ths.

2x48= $96

6x4= 24 slices to be sold in 4ths.

24x3=$72

96-72= $24

They will make 24 more dollars if they sell slices in eighths.

6 0

2 years ago

Read 2 more answers

Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does a 0 r

MrRa [10]

This could be a situation in which items are both bought and sold. In calculating the inventory, positive numbers represent items bought, negative numbers represent items sold and 0 would be no items in the inventory.

Another type of situation would be the displacement of an object from the original position. Where 0 would represent the original/starting position, positive values would represent distance moved forward, negative values represent distance moved backwards.

4 0

2 years ago

The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the

sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

$v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2$

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

$v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}$

When we use this to replace the 't" in the displacement formula, we et:

$y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}$

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity $v_0$ , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0

2 years ago