Answer:
O lies on the perpendicular bisector of AB. ... Then, O' will lie on the perpendicular bisector PQ and RS. We know that, two lines cannot intersect at more than one point, So O' must coincide with O. Hence, there is one and only one circle passing through three non collinear points
Step-by-step explanation:
Answer:
1. p->q
2. p<->q
3. :.p^q
Step-by-step explanation:
I hope this will help you
Answer:
Step-by-step explanation:
line 1 m=y2-y1 / x2-x1 [formula for slope ]
m= 0 - (-3) / 8-(-4)
m= 3 /12
m= 1/4 slope of line 1
line2
m = 2-6 / 0-(-1)
m = -4 / 1
m = -4 slope of line 2
line 3
m = -4 - (-7) / -3 - 6
m = 3 / -9
m = - 1/3 slope of line 3
lines 1 & 2 perpendicular b/c they are reciprocals with a sign change :)
lines 1 & 3 neither.. differet slopes and not reciprocals
lines 2 & 3 perpendicular b/c they are reciprocals with a sign change :)
Answer:
26
Step-by-step explanation:
add both expressions to equal 90 (bc of the right angle)- x+11+2x+1=90
when you solve, you get x=26
X = 3
y = -3
You will see this using any graphing tool at your disposal.
