Answer:
Step-by-step explanation:
for the first equation x= -2 and y=-7
the second equation x=3 and y is 3 now just plot x and y from the same equation on the same line
Yes to every single one except the 4/5
:)
9514 1404 393
Answer:
14.14
Step-by-step explanation:
The diagonal of a square is √2 times the side length.
AC = AB×√2
AC = 10√2 ≈ 14.14
_____
The diagonal of a square is the hypotenuse of an isosceles right triangle. If the sides of that are s and the diagonal is d, the Pythagorean theorem tells us ...
d² = s² + s²
d² = 2s²
d = (√2)(√s²) = s√2
This relation holds for <em>any isosceles right triangle</em>, not just for the diagonal of this square. It is useful to remember.
Answer:
2%
Step-by-step explanation:
20% takes 10 years to decay
To find per year decay, we divide the percentage by the number of years, so we get unit rate of years {per year]. Thus we have:
20%/10 = 2% per year
It's that simple.
Hence, the percentage by which the substance decays each year is 2%
Answer:
a) 

b) 
c) 
Step-by-step explanation:
From the question we are told that
Sample space S=50
Sample size n=30
a)Generally the sample space S is

The probability measure is given as


b)
Generally the probability that the class hangs Wisconsin’s flag on Monday, Michigan’s flag on Tuesday, and California’s flag on Wednesday is mathematically given as
Probability of each one being hanged is

Therefore



c)Generally the probability that Wisconsin’s flag will be hung at least two of the three days is mathematically given as
Probability of two days hung +Probability of three days hung
Therefore


