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2 years ago

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Help please. I don't understand

1 answer:

inna [77]2 years ago

7 0

In the middle of the first squre

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Plz help ASAP! Algebra 1 question. I will mark brainiest and give 50 points.

Musya8 [376]

Answer:

it is 20x - 11 = 5x + 11

Step-by-step explanation:

hope this help :)

8 0

2 years ago

Read 2 more answers

A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

monitta

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if it is 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if it is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that $\mu = 0.7$

Survey of 35 people. From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that $n = 35, X = 0.95, s = 0.44$

Calculate the test statistic

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}$

$t = 3.36$

The test statistic is t = 3.36.

7 0

3 years ago

During the grand opening of the T-Shirt Shack at the Madera County Emu Farm, four of the emus broke through the fence and attack

Irina-Kira [14]

Given :

p = 0.68

margin of error, E = 0.1

99% confident interval

alpha, α = 1 - 0.99

= 0.01

$\frac{\alpha }{2}=\frac{0.01}{2} = 0.005$

∴ $z_{\alpha/2}=z_{0.005}=2.5758$ (z-critical value)

Sample size = $z_{\alpha/2} \times \frac{p(1-p)}{E^2}$

$=(2.5758)^2 \times 0.68 \times \frac{(1-0.68)}{0.1^2}$

$= 6.63475 \times 0.68 \times \frac{0.32}{0.01}$

= 144.37

= 145 (rounded off)

Therefore, there are 145 businesses does she need to sample to meet this criteria.

6 0

3 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

4 0

3 years ago

The question for this is "Kiera plays a board game with a spinner like the one shown below.

Dennis_Churaev [7]

The answer is C
This is because the Go Back space is twice as big as the Return To Start space

8 0

3 years ago