Answer:
Step 1
Step-by-step explanation:
You distributed the 2 in 2(x-4) to get 2x-8
I think the answer would be true
To find the zeroes you make the function equal to zero and then solve.

Then factor out the x to get a quadratic inside the parentheses.

Factor the inside quadratic formula.

Lastly, use the zero product property to solve.
