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SOVA2 [1]
3 years ago
7

Horses and zebras can be bred to produce a zorse, which is sterile. Which is most likely the reason zebras and horses are consid

ered separate species?
Biology
2 answers:
Sladkaya [172]3 years ago
8 0
I believe it would be the second option which is B. I just took the unit test which has this question.
S_A_V [24]3 years ago
3 0
<span>Due to the fact that horses and zebras can be bred to produce any offspring means that they belong to the same genus (Equus). However the offspring that comes about as a result of this cross breeding (zebroid/zorse) is not a fertile offspring. From these results we can conclude that the zebra and the horse are classified into different species. A horse has 64 chromosomes while a zebra has 46 or 32 chromosomes depending on the species. Their offspring often ends up having 54 chromosomes. This difference in chromosomes dictates that the female offspring not sufficiently fertile and the male sterile.</span>
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Why is it safer to use solar energy than chemical energy?
Anna71 [15]
Solar energy is more Natural since it comes from the sun and easier to harness, while chemical energy is Dangerous because it may fail and cause damage.
7 0
3 years ago
2. List three sources of error that could account for the differences between your values for the enthalpy of fusion of water an
Dvinal [7]

1 trial :  nothing is given for result comparision - so we have no idea if it's a mistake.

2nd trial : The results can be compared - if varies, one may go wrong, but which one?

3rd trial : If 3rd result is different from 1st and 2nd, it is unreliable.

calculating enthalpy of fusion. M, C and m,c = mass and specific heat of calorimeter and water, n, L = mass and heat of fusion of ice; T = temperature fall.

L = (mc+MC)T/n.

c=4.18 J/gK. assuming copper calorimeter , so C=0.385 J/gK.

1. M = 409g, m = 45g. T = 22c, n = 14g

L = (45*4.18+409*0.385)*22/14 = 543.0 J/g.

2. M = 409g, m = 49g, T = 20c, n = 13g

L = (49*4.18+409*0.385)*20/13 = 557.4 J/g.

3. M = 409g, m = 54g, T = 20c, n = 14g

L = (54*4.18+409*0.385)*20/14 = 547.4 J/g.

(i) Estimate error in L from spread of 3 results.

Average L = 549.3 J/g.

squared differences average (variance) = (6.236^2+8.095^2+1.859^2)/3 = 35.96

standard deviation = 5.9964

standard error = SD/(N-1) = 5.9964/2 = 3 J/g approx.

% error = 3/547 x 100% = 0.5%.

(ii) Estimate error in L from accuracy of measurements:

error in masses = +/-0.5g

error in T = +/-0.5c

For Trial 3

M = 409g, error = 0.5g

m = 463-409, error = sqrt(0.5^2+0.5^2) = 0.5*sqrt(2)

n =(516-463)-(448-409)=14, error = 0.5*sqrt(4) = 1.0g

K = (mc+MC)=383, error = sqrt[2*(0.5*4.18)^2+(0.5*0.385)^2] = 2.962

L = K*T/n

% errors are

K: 3/383 x 100% = 0.77

T: 0.5/20 x 100% = 2.5

n: 1.0/14 x 100% = 7.14

% errors in K and T are << error in n, so ignore them.

% error in L = same as in n = 7% x 547.4 = 40

The result is (i) L= 549 +/- 3 J/g or (ii) L = 550 +/- 40 J/g.

Both are very far above  334 J/g, so there is at least one systematic error  

e.g: calorimeter may not be copper, so C is not 0.385 J/gK. (If it was polystyrene, which absorbs/ transmits little heat, the effective value of C would be very low, reducing L.)

Using +/- 40 is best.

However, the spread in the actual results is much smaller

* measurements were "fiddled" to get better results; other Trials were made but only best 3 were chosen.

<h3>Other sources of error: </h3>

L=(mc+MC)T/n is too high, so n (ice melted) may be too small, or T (temp fall) too high - why?

* we have assumed initial and final temperature of ice was 0c, it may actually have been colder, so less ice would melt -which explain small values of n

* some water might have been left in container when unmelted ice was weighed (eg clinging to ice) - again this could explain small n;

* poor insulation - heat gained from surroundings, melting more ice, increasing n - but this would reduce measured L below 334 J/g not increase it.

* calorimeter still cold from last trial when next one started, not given time to reach same temperature as water - this would reduce n.

3 0
3 years ago
Two garden plots were planted with corn. The soil was similar in each, and equal amounts of water were applied to each plot. One
neonofarm [45]

Answer: control plot

Explanation:

Control plot refers to the plot that couldn’t receive the experimental treatment such as fertilizer and or variable being tested while another plot receive fertilizer can give proper yield.  It is just because, fertilizer is the main source or substance that provides chemical elements that may necessary for corn plant growth and its development.  There are two main types of fertilizers such as organic and inorganic, among them organic fertilizer usually contains different nutrients that broken down by different microorganism and then used by such plants to grow effectively.

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3 years ago
Cnidocytes are found in _____.
Gnesinka [82]

Answer:

phylum Cnidaria

Explanation:

Cnidocytes represent a group of living organisms, whose members are Jellyfish, Sea Anemone, Hydra, Portuguese Caravel. Cnidocytes are found in the Cnidaria phylum.

Cnidaria, known in the past as coelenterates, are relatively simple animals with no circulatory and respiratory system, all of which are done through the diffusion process. They have diffuse nervous system and metabolism products are eliminated by mouth. The locomotion occurs through jets of water in the jellyfish and some polyps move slowly dragging or somersaulting.

8 0
3 years ago
Which best describes how blood pressure is measured and why it is important?
Slav-nsk [51]

Answer:

A) Blood pressure measures pressure on the arteries and can be an indicator of an unhealthy cardiovascular system.

Explanation:

Blood pressure is the amount of pressure that the blood puts on the arteries as it flows through them.

6 0
3 years ago
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