Answer:
<h2><em><u>True</u></em><em><u> </u></em></h2>
Explanation:
<u>It's</u><u> </u><u>a</u><u> </u><u>true</u><u> </u><u>statement</u><u> </u><u>as</u><u>,</u>
- When we inhale the diaphragm moves downwards and the rib cage moves upwards and outwards to let enter the outside air containing oxygen come in.
- While we exhale the diaphragm comes to its position and the rib cage move downwards and inwards to let out the inside carbon-dioxide and other games out.
<u>Hence</u><u>,</u><u> </u><u>we</u><u> </u><u>can</u><u> </u><u>conclude that</u><u> </u><u>breathing involves the movement of diaphragm and Rib cage</u><u>.</u>
Answer:Exocrine glands are glands that secrete substances onto an epithelial surface by way of a duct.
A manifestation of local blood flow regulation.
Answer:
The recombination frequency between two genes exhibits a positive correlation with the distance between them, that is, farther they are, and more will be the chance of recombination. Thus, recombination frequency is used to signify distance among the two genes, for example, 1 percent recombination frequency demonstrates distance of 1 map unit.
Let us consider that the heterozygous female of genotype AaBb can generate four kinds of gametes, that is, AB, Ab, aB and ab. Of these, the two gametes are the outcomes of recombination, or it can be said that 50 percent are recombinants. Thus, it can be concluded that in case of two linked genes, the maximum probable recombination frequency is 50 percent.
This shows that any genes, which are distant than 50 map units will function as unlinked and will function as if they were on distinct chromosomes, and the frequency of recombinant frequency will be 50 percent.
In the given question, it is given that the map distance between the two genes is 80 map units, that is, more than 50 map units. The maximum probable recombinant offspring will be 50 percent of the entire offspring.
