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rosijanka [135]
3 years ago
11

Whats -1 1/10 divided by -11/10

Mathematics
2 answers:
Bogdan [553]3 years ago
4 0

Answer:

1

Step-by-step explanation:

Any number divided by itself is 1

Dafna11 [192]3 years ago
3 0

Answer:

-1 \frac{1}{10} \div -\frac{11}{10} = \frac{1}{100}

Decimal:

0.01

Step-by-step explanation:

-1\frac{1}{10}\div -\frac{11}{10}

Convert mixed numbers to improper fractions: 1 \frac{1}{10}  = \frac{11}{10}

-\frac{11}{10}\div -\frac{11}{10}

\frac{\frac{11}{10} }{-11} = -\frac{11}{110}

=-\frac{-\frac{11}{110}}{10}

Simplify \frac{-\frac{11}{110}}{10} : -\frac{11}{1100}

=-\left(-\frac{11}{1100}\right)

Cancel \frac{11}{1100}: \frac{1}{100}

=-\left(-\frac{1}{100}\right)

Apply rule -\left(-a\right)=a :

=\frac{1}{100}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

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What is the product of 0.46 and 35
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. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
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