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labwork [276]
2 years ago
8

HELP, I’M STUCK !

Mathematics
1 answer:
vaieri [72.5K]2 years ago
6 0

Since P(<em>X</em> = <em>x</em>) = 0.3 for all 0 ≤ <em>x</em> ≤ <em>α</em>, we have

\displaystyle\int_{-\infty}^\infty P(X=x)\,\mathrm dx=1\implies0.3\int_0^\alpha\mathrm dx=0.3\alpha=1\implies\alpha=\dfrac{10}3

So,

P(X>2) = \displaystyle\int_2^\infty P(X=x)\,\mathrm dx=0.3\int_2^{\frac{10}3}\mathrm dx

P(X>2)=0.3\left(\dfrac{10}3-2\right)=\boxed{\dfrac25}

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Use the long division method to find the result when 2 x 3 + 7 x 2 + 14 x + 12 2x 3 +7x 2 +14x+12 is divided by 2 x + 3 2x+3
egoroff_w [7]

Answer:

2 x 3 + 7 x 2 + 14 x + 12÷ 2x+ 3 = <u> x² +2x+ 4  </u>

Step-by-step explanation:

We multiply the first term 2x of the divisor with a term ( quotient) to get the first term of the dividend. Then we multiply the same term with each term of the divisor  and subtract it from the dividend. The process continues unless we get the zero or a much smaller number than the dividend as the remainder

              <u>  x² +2x+ 4                        </u>

2x+3    ║2 x 3 + 7 x 2 + 14 x + 12

               2x³ + 3x²

     <u>            -      -       </u>

                         4x² +14x+12

                          4x²+ 6x

                    <u>     -        -      </u>

                                   8x+12

                                     8x+12      

                               <u>    -        -   </u>

                              <u>        0         </u>

4 0
2 years ago
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
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Kitty [74]

Answer:

Step-by-step explanation:

x=-1-2y

-2-4y-3y-12=0

-7y=14

y=-2

x=3

3 0
2 years ago
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