Gina will earn at least 30% of intreat in the next 2 year .
Answer:
the answer is (6, 1)
Step-by-step explanation:
x² + y² - 12 x - 2 y + 12 = 0
(x²-12x) +(y² -2y) +12 = 0
(x²-2(6)(x)+6²)-6² +(y² -2y+1) -1+12 = 0
(x-6)² +(y-1)² = 5²
the center of a circle is (6, 1)
Answer:
5 units
Step-by-step explanation:
here;
perpendicular (p)= 3
base (b) = 4
hypotenuse (h) = c= ?
By Pythagorean relationship;
h²=p²+b²
or, h= √(p²+b²)
or, c= √(3²+9²)
or, c= √25
hence, c=5
Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola?
.
At this point you have three parameters to play with, and from the fact that
we can already fix one of them, in particular
. At this point I would recommend picking an easy value for one of the two, let's say
(or even
, it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms: 
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: 
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need
, and at that point the first condition is guaranteed; using the second to find k we get 

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

Sky is the limit.
The mean of those sets of numbers are 17.5