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sergeinik [125]
3 years ago
8

Jeo is comparing the price of different boxes of cereal. One box has 16 oz. and costs $3.50. Another costs $3.89 for a 24 oz. bo

x. What is the difference in cost, in dollars, per ounce between the two boxes of cereal?
Mathematics
1 answer:
velikii [3]3 years ago
7 0

Answer:

The difference in cost, in dollars, per ounce between the two boxes of cereal is $0.06.

Step-by-step explanation:

☆Let's solve using proportion.

☆One box:

\frac{16 \: oz.}{3.50 \: dollars}  =  \frac{1 \: oz.}{x}  \\  \\  \frac{3.50}{16}  =  \frac{16x}{16 }  \\  \\ 0.22 = x

☆Another box:

\frac{24 \: oz.}{3.89 \: dollars}   = \frac{1 \: oz.}{x }  \\  \\  \frac{3.89}{24}  =  \frac{24x}{24}  \\ \\ x = 0.16

☆All we need to do is subtract: 0.22 - 0.16 = 0.06

☆The difference in cost, in dollars, per ounce between the two boxes of cereal is $0.06.

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A bank charges $3 each time you use an out-of-network ATM. At the beginning of the month, you have $1500 in your bank account. Y
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Answer:

y=-\frac{63}{1} x+1500

Step-by-step explanation:

Create a table:

1500 - 63(0) = 1500

1500 - 63(1) = 1437

1500 - 63(2) = 1374

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Turn them into ordered pair:

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(1, 1437)

(2, 1374)

(3, 1311)

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3 years ago
Help me pwees no links<br><br> what is 159 rounded to the nearest tenth minus 10
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3 years ago
Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

⇒ 3x=\pm \frac{\pi}{4}

⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

x = \pm cos^{-1}(y)+ 2k\pi

⇒ x = \pm \frac{\pi}{12}+ 2k\pi , k is any integer .

At k=0,

⇒ x =\frac{\pi}{12} ,

At k=1,

⇒ x = - \frac{\pi}{12}+ 2\pi

⇒ x = \frac{23\pi}{12}

Therefore , Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

5 0
3 years ago
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