Since the original cost is 2700, the fraction 1890 is of 2700 is 1890/2700. Since they both have a 0 at the end, we can cross that out to get 189/270. Next, since their digits add up to factors of 3 (1+8+9=18 and 2+7=9), we can factor 3 out to get 63/90. Repeating the process since these are factors of 3 too, we get 21/30. Doing it yet again since 21 and 30 are factors of 3, we get 7/10 as our answer
Answer:
I hope it helps it was the best I can do.
Step-by-step explanation:
-x12 + x7 = 0
Factorization:
−x7(x − 1)(x4 + x3 + x2 + x + 1) = 0
Solutions based on Jenkins–Traub algorithm:
x1 = … = x7 = 0
x8 = 1
x9 = −0.809017 − 0.587785i
x10 = −0.809017 + 0.587785i
x11 = 0.309017 − 0.951057i
x12 = 0.309017 + 0.951057i
The answer is. D. (-6,7)
To solve the exercise you should be aware that you should primarily locate the location of park on the abscissa-x_axis ( West - East. ) followed by locating the latter on the ordinate- Y_axis (South - North). So first u start by drawing a line perpendicular ( makes a 90 degrees ) to the X_axis to find that it cuts it in a point of coordinates (-6,0) and then do the same on the Y_axis to find that it cuts it in a point of coordinates (0,7). Thus you conclude that the park is found on (-6,7) count 6 boxes to the left-west and then 7 upwards- north.
Answer:16 coins and x+y
Step-by-step explanation:
You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.
Use binomial theorem.
n = 11
k = 10,11
p = 1/2
