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3 years ago

Can someone please help me with this ASAP!! (will mark as brainliest if correct)

Mathematics

2 answers:

sattari [20]3 years ago

6 0

Answer:

P = 6x-2

x = 14

Step-by-step explanation:

To find the perimeter, we add the sides

P = 4x-8 + 3-2x + 5x+3

Combine like terms

P = 4x-3x+5x -8+3+3

= 6x -2

Now we know the perimeter

82 = 6x-2

Add 2 to each side

82+2 = 6x-2+2

84 = 6x

Divide each side by 6

84/6 = 6x/6

14=x

Vladimir [108]3 years ago

3 0

Answer:

A) 7x - 2

B) x = 12

Step-by-step explanation:

4x - 8 + 3 - 2x + 5x + 3

7x - 2

7x - 2 = 82

7x = 84

x = 12

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3 years ago

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3 years ago

A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

marin [14]

Answer:

$Range = 85$

$\sigma = 28.71$

$Interval = [666.78, 781.62]$

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

$Range = Highest - Least$

From the dataset:

$Highest = 772$

$Least = 687$

So:

$Range = Highest - Least$

$Range = 772-687$

$Range = 85$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

First, calculate the mean

$\bar x = \frac{769 +691 +............+715}{25}$

$\bar x = \frac{18105}{25}$

$\bar x = 724.2$

So, the standard deviation is:

$\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}$

$\sigma = \sqrt{\frac{20604}{25}}$

$\sigma = \sqrt{824.16}$

$\sigma = 28.71$

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

$Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]$

$Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]$

$Interval = [666.78, 781.62]$

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2 years ago

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1/3 from 6 (the amount of girls with glasses) / 18 (total number of students)

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