1:04pm pretty sure i think that’s right
You solve for x and get x<-2 or x>= -1/2 and then graph
Answer:
C. The distribution for town A is symmetric, but the distribution for
town B is negatively skewed.
Step-by-step Explanation:
From the box plots attached in the diagram below, which shows data of low temperatures for town A and town B for some days, we can compare the shapes of the box plot by visually analysing both box plots and how the data for each town is distributed.
=> For town A, the shape of the box plot is symmetric because both quartiles seem equal, and the median also divides the rectangular box into two equal halves. Both whiskers also appear to be of equal lengths.
The box plot for Town A takes a symmetric shape, and this shows a typical normal distribution of data.
=> On the other hand, Town B data distribution is different. The median seem close to the top half of the box and does not divide the box into equal halves. This shows the distribution is skewed. Since the whisker is shorter from the upper end of the box to the left side, we can infer that the distribution for Town B is skewed to the left, and it is negatively skewed.
=> The right comparison of the shapes of the box plots is "C. The distribution for town A is symmetric, but the distribution for town B is negatively skewed."
Answer: -2 4/15
Step-by-step explanation: To properly subtract, we need to find a common denominator. We can list the multiples of 3 and 5 to find the common denominator:
3: 3, 6, 9, 12, 15
5: 5, 10, 15
The first common multiple we see is 15.
Calculation:
3 · 3 = 9
9 + 1 = 10
3 1/3 = 10/3
5 x 5 = 25
25 + 3 = 28
-5 3/5 = -28/5
Now to convert into fifteen as the denominator:
-28/5 = -28 x 3/5 x 3 = -84/15
10/3 = 10 x 5/3 x 5 = 50/15
Now to subtract accordingly:
50/15 - 84/15 = -34/15
Final answer: -34/15 (can be reduced to -2 4/15).
bearing in mind that a <u>circle</u> means the round thing, so only the points on the round thing are ON the circle, others like the RC chord or the PQ diameter or the point C are NOT ON the circle.