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4 years ago

Round to the nearest tenth 10.357

2 answers:

6 0

To round 10.357 to the nearest tenth, you would need to look at the hundredths place. Five is in the hundredths place so that tells you to round up to 10.4.

madam [21]4 years ago

5 0

The answer is 10.4 because 5 is counted as higher so it's 10.4.

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What is the simplified form of the quantity 1 over b minus 1 over a all over the quantity 1 over b plus 1 over a?

jolli1 [7]

Option B: (b-a)/(b+a) is the correct answer

Step-by-step explanation:

The given expression is;

$\frac{\frac{1}{b}-\frac{1}{a}}{\frac{1}{b}+\frac{1}{a}}$

First of all we have to take LCM in both numerator and denominator

So,

$=\frac{\frac{b-a}{ab}}{\frac{b+a}{ab}}$

The reciprocal of the denominator will be multiplied with the numerator for simplification

So,

$=\frac{b-a}{ab} * \frac{ab}{b+a}\\= \frac{b-a}{b+a}$

Hence,

Option B: (b-a)/(b+a) is the correct answer

Keywords: Fractions, expressions

Learn more about fractions at:

#LearnwithBrainly

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3 years ago

What is 8 4/8 - 4 5/6?

Vlad1618 [11]

Answer:

3.667

Step-by-step explanation:

I know math (and how to use a calculator)

5 0

3 years ago

Read 2 more answers

What is the slope of this equation? y= -1/2x −3 option -3 0 -1/2

marissa [1.9K]

Answer:

The slope is -1/2

The slope is after the "y=" but before the "x" variable.

3 0

4 years ago

Write an equivalent expression for the 4th root of 324m^12 * the cubed root of 64k^9. Need help!

Elis [28]

Answer:

The equivalent expression to the givan expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

8 0

3 years ago

The sum of a number and 72 times its reciprocal is -17. Find the number

butalik [34]

Let, the number = x

Then, x + 72/x = -17

x² + 72 = -17x

x² + 17x + 72 = 0

x² + 8x + 9x + 72 = 0

x(x + 8) 9(x + 8) = 0

(x + 8)(x + 9) = 0

x = -8 OR -9

In short, Your Number would be: Either -9 or -8

Hope this helps!

3 0

3 years ago