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dem82 [27]
4 years ago
14

There are 235 seventh-grade students going on a field trip. The school has 5 buses to take the students. Each bus has 22 seats,

and 2 students can sit in each seat. Based on this information, how many students will not be able to ride on a bus for the field trip?
Mathematics
1 answer:
trasher [3.6K]4 years ago
3 0

15 students will not be able to ride on bus for the field trip.

Step-by-step explanation:

No. of seats in one bus = 22 seats

1 seat is for 2 students, therefore, one bus can sit students;

No. of students in one bus = 22*2 = 44 seats

Total buses = 5

One bus can have 44 students, 5 buses can have;

5 buses = 44*5 = 220 students

Total students = 235

As the buses can have 220 students;

Students left = Total students - No. of students in 5 buses

Students\ left=235-220=15\ students

15 students will not be able to ride on bus for the field trip.

Keywords: multiplication, subtraction

Learn more about subtraction at:

  • brainly.com/question/7419893
  • brainly.com/question/730852

#LearnwithBrainly

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Ne4ueva [31]
(3x^3 - 5x^2 -4x + 4) / (x-2) = (3x-2)(x+1) when x ≠2
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3 years ago
Can someone please help me with my math homework
Natali5045456 [20]
Josephine travels 32500+78000 yards at 60 mph
=110500yards
=62.78miles

time = distance/spped
time = distance/60
time=62.78/60
time=1.05 (1 hour 5 mins)

Marcus travels 78000(2)(square) +32500(2)
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6 0
3 years ago
Researchers have concluded that a dry basin began to fill with water in 1880. the water level rose an average of 1.6 millimeters
docker41 [41]

Answer:

  1. the domain is [0,129]
  2. 112 mm
  3. 1942

Step-by-step explanation:

1. The function is good for years 1880 to 2009, 0 to 129 years after 1880. Values of x can be anything in the domain [0, 129].

__

2. 1950 -1880 = 70. The year 1950 corresponds to x=70, so the function tells us the water level rose ...

  f(70) = 1.6·70 = 112 . . . . . mm

__

3. We want to find x when f(x) = 100. That will be the solution to ...

  100 = 1.6x

  100/1.6 = x = 62.5

Then 62.5 years after 1880 is year 1942.5. The water level was 100 mm higher than in 1880 in the year 1942.

3 0
3 years ago
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
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Why do althletes stretch before a game
alex41 [277]

Answer:

so they dont get cramps or chairly horses

Step-by-step explanation:

3 0
4 years ago
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