Question

Joshua spins a spinner twice. The spinner consists of 3 equally spaced colors, Red, Blue, and Yellow. What is the probability that the spinner will stop on green and then yellow? ASAP

Answer 1

Answer:

$\dfrac{1}{9}$

Step-by-step explanation:

Given a spinner with 3 equally spaced colors Red, Blue, Yellow.

The colors are equally spaced, therefore probability of each color must be same.

i.e. Probability of occurrence of any one color in one spin is $\frac{1}{3}$.

To find:

Probability that spinner will stop one green in first spin and yellow in the second spin = ?

Solution:

As all the colors are equally likely to occur, so

Probability of green color in the first spin, P(G) = $\frac{1}{3}$

Probability of yellow color in the second spin, P(Y) = $\frac{1}{3}$

As we can observe that occurrence of any color in the second round of spin is not dependent on the color occurrence in the first spin, therefore these are the independent events.

P(G and Y) = P(G) $\times$ P(Y)

$\Rightarrow P(G\ and\ Y) = \dfrac{1}{3} \times \dfrac{1}{3}\\\Rightarrow P(G\ and\ Y) = \bold{\dfrac{1}{9}}$

Therefore, the required probability is

$\dfrac{1}{9}$.