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Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
Let x be the first odd integer.
x + 2 the second
x + 4 the third
x + 6 the fourth
x + 8 the fifth.
add them up and you get 5x + 20
set 5x + 20 = 145 and solve for x.
5x=145-20
5x=125
x=25
answer=25,27,29,31,33
The square root<span> of a number is a value that, when multiplied by itself, gives the number.</span><span> </span>
<h2>Just some examples...</h2>
2z+4=12
2(4)+4=12
<em>8+4=12</em>
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5z*2=40
5(4)*2=40
<em>20*2=40</em>
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