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3 years ago

Help guysss :((( please it's due Monday :((((((((((( pleaseeeeeeweeeee

Mathematics

2 answers:

yanalaym [24]3 years ago

4 0

Left over is 456 minus total of A+B+C
456-334=122
C d are equal so 122/2=61

galben [10]3 years ago

3 0

Try this: Add up the given widths of the first 3 bookcases, in cm. This will be a constant. Now write "-2w" after that sum, to represent two more bookcases of unknown widths w. Finally, use the inequality symbol (less than or equal to) and the given wall length to complete this inequality.

Solve it for w, writing your answer as another inequality.

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PLEASE HELP ME NOW!!!!!!!

Mars2501 [29]

Answer:

Step-by-step ex$ in 6 in 14 dt lenght times width times hight planation:

3 0

2 years ago

If a cone has a radius of 2 cm and a height of 10 cm, what is the volume?

BARSIC [14]

Answer:

41.89

explanation:

the formula for finding the volume of a cone would be pi x r^2 x h/3;

3.14 x 4 x 3.33333333, which equals 41.89.

hope that helps :)

5 0

2 years ago

Read 2 more answers

melanie made a circular necklace she puts beads evenly spaced around the necklace if the 4th bead is directly across from the 11

dangina [55]

Answer:

Step-by-step explanation:

If the 4th lies opposite the 11th, then you know the 3rd lies opposite the 10th, the 2nd opposite the 9th, and the 1st opposite the 8th; meanwhile, in the reverse direction you'd find that the 5th lies opposite the 12th, the 6th opposite the 13th, and the 7th opposite the 14th. Move up one more bead and you're back at the 1st, which you already know lies opposite the 8th. Therefore there are 14 total bead

4 0

2 years ago

11th grade geometry:

Aliun [14]

Answer:

The perimeter is 72 units and the area is 149 square units.

Step-by-step explanation:

$\triangle SBA$ has coordinates $S(15,-8),B(-2,21)$ and $A(0,0)$

Using the distance formula.........

Length of side $SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}$

Length of side $BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}$

Length of side $AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17$

So, the perimeter of the triangle will be: $(SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72$ units. (Rounded to the nearest unit)

The height of the triangle for the corresponding base $SB$ is 8.89 units.

Formula for the Area of triangle, $A= \frac{1}{2}(base\times height)$

So, the area of the $\triangle SBA$ will be: $\frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149$ square units. (Rounded to the nearest unit)

3 0

3 years ago

Pleas help this is due today!!

harkovskaia [24]

I can tell this activity is about graphing, but the writing is barely legible, can you re-upload the pictures or write it out?

8 0

3 years ago