(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15
Recall that in statistics, the mode is the value that appears most frequently in a set of data. You may find it useful to represent the data in statistical graphs such as dot plots or bar charts. In this case, we will use the following chart
As we can see from the image, The most frequently used numbers are 19 and 21. We are dealing with a bimodal data set. The mode is given by 19 and 21.
This is going to require a good bit of division. I am going to turn the mixed fractions into improper fractions. Remember that to divide fractions, you take the 2nd fraction, flip it, and multiply.
First (2 1/2)/(1/4) = (5/2)(4) = 20/2 = 10
Next, 3/(1/4) = 3(4) = 12
Lastly, (3 1/4)/(1/4) = (13/4) x 4 = 52/4 = 13
This means we need 10 rows of 12, 13 high. 10(12)(13) = 1560 cubes.
Answer: 39
Step-by-step explanation:
6(8-3)+3(7-4) 1. Make sure to multiply what's in the parentheses first.
6(5)+3(3) 2. Multiply before you add the coefficients
30+9 3. Add
Answer is 39
Answer:+ 3*1 = 2 + 3 = 5 3 + 7 =17 => 3 + 7*2 = 3 +14 = 17 4 + 5
Step-by-step explanation:
