Question

If one half of an integer is added to one fifth of the next consecutive integer, the sum is 10. Find the integers.

Answer 1

1/2x + 1/5(x + 1) = 10
1/2x + 1/5x + 1/5 = 10
5/10x + 2/10x = 10 - 1/5
7/10x = 50/5 - 1/5
7/10x = 49/5
x = 49/5 * 10/7
x = 490/35
x = 14

x + 1 = 15

ur integers are 14 and 15

Answer 2

Let 1st integer be x and next consecutive be x+1
1/2•x + 1/5•(x+1) = 10
x/2 + x/5 + 1/5 = 10
-1/5 -1/5
x/2 + x/5 = 49/5
(x/2)•5/5 + (x/5)•2/2 = 49/5
5x/10 + 2x/10 = 49/5
7x/10 = 49/5
•10 •10
7x = 98
÷7 ÷7
x = 14 --> 1st integer
x+1 = 14+1 = 15 --> next consecutive integer