Answer:
The less mass in a given volume of air the less dense the air is going to be.
Answer:
Explanation:
Given that:
The argon atoms are excited into an excited state before emitting the 488.0 nm laser.
the energy of the first ionization energy of argon is 1520 kJ mol-1.
SInce 1 eV = 96.49 kJ/mol
Therefore, the energy of the first ionization energy of argon in eV is = ( 1520/ 96.49) eV
= 15.75 eV
To find where the energy level of the excited state lies below the vacuum energy level, let's first determine, the energy liberated by using planck expression.
Converting Joules (J) to eV ; we get,
E = 2.53 eV
The energy levels of the first exited state = -13.223 eV
Answer:
0.24 mol/L.
Explanation:
- Ca(OH)₂ dissociates in solution according to the equation:
<em>Ca(OH)₂ → Ca²⁺ + 2OH⁻.</em>
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Every 1.0 mol of Ca(OH)₂ dissociates to give 2.0 moles of OH⁻.
∴ The no. of moles of OH⁻ produced from 0.06 mol of Ca(OH)₂ = (2 x 0.06 mol) = 0.12 mol.
<em>∴ [OH⁻] = no. of moles / V of the solution</em> = (0.12 mol)/(0.5 L) = <em>0.24 mol/L.</em>
Answer:
94.1 %
Explanation:
We firstly determine the equation:
2H₂O + O₂ → 2H₂O₂
2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.
We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol
Certainly oxygen is the limiting reactant.
2 moles of water react to 1 mol of oxygen.
13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)
As we determine the limiting reactant we continue to the products:
1 mol of O₂ can produce 2 moles of H₂O₂
Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles
We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g
That's the 100% yield or it can be called theoretical yield.
Percent yield = (Yield produced / Theoretical yield) . 100
(100g / 106.25 g) . 100 = 94.1 %
Light Pollution affects both indirectly by inter fearing with and destroying the life cycles of the pollinators or other animals that interact with them.
