Br2 5mol take a 10 mol Br atoms mol
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
= 25/1000 liter
= 0.025 liter
V2 = 18 ml
= 18/1000 liter
= 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
= (1 * 0.018)/0.025
= 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
Answer:
= 331.81 g
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
Therefore;
Moles = Molarity ×Volume in liters
= 0.35 M × 1.575 L
= 0.55125 Moles
But; Molar mass of Ba3(PO4)2 is 601.93 g/mol
Thus;
Mass = 0.55125 moles × 601.93 g/mol
<u>=331.81 g</u>
<h3>
Answer:</h3>
5.89%
<h3>
Explanation:</h3>
We are given;
- Mass of the solute, LiOH as 40.1 g
- Mass of the solvent, H₂O as 681 g
We are required to calculate the mass percent composition of solution;
- But; How do we calculate the mass percent composition of a solution?
- We use the formula;
- Mass composition of a solution = (Mass of solute/mass of solution) 100%
Mass Percent = (40.1 g/681 g)× 100%
= 5.888 %
= 5.89%
Therefore, the mass percent composition of the solution is 5.89%
Answer:
Explanation:
159 mL of .135 M benzoic acid will contain
.159 x .135 = .021465 moles of benzoic acid.
Molecular weight of benzoic acid = 122 gm
grams of .021465 moles = 122 x .021465 = 2.6 grams .
So 2.6 grams of benzoic acid will be required .
