The discriminant of a quadratic equation has a value of 0. Which of the

A 1 newton force will stretch a spring 1 meter. The spring/mass system is damped by a force that is 8 times the instantaneous ve

sukhopar [10]

Answer:

Step-by-step explanation:

Given the mass is m =16kg, and 1N force will stretch the spring 1 m.

That is, F =1N,Z =1m. Now find the spring constant k:

F = kL = 1 = k(1) = k= 1N/m.

The damping force is 8times the instantaneous velocity, this means β = 8,

and the external force is f(t) = 0

Initially the object compressed 0.6m above equilibrium position,

with the downward velocity is 2m/s.

The differential equation for a spring mass system with

damping force and extemal force is: mx" + βxt + kx = f(t).

so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.

Now solve the DE:

The auxilary equation for the homogeneous equation is 16x"+8x'+x=0

solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.

Then the general solution for the homogenous system is: $x(t)=c_1e^{-t/4} +c_2te^{-t\4}$ .

Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:

$x(0)=c_1e^{0} +c_2(0)e^{0}=-0.6=c_1\\x'(t)=-\frac{1}{4}c_1e^{-t/4}+c_2e^{-t/4}-\frac{1}{4}c_2te^{-t/4}\\x'(0)=-\frac{1}{4}c_1e^0+c_2e^0-\frac{1}{4}c_2(0)e^0=2=-\frac{1}{4}(-0.6)+c_2=c_2=1.85$ .

Hence, $x(t) =-0.6e^{-t/4}+1.85te^{-t/4}$ .

5 0

3 years ago

3,152 divided by 16 is what

juin [17]

The quotient is<em> 197</em> .

You have a choice of 3 tools to use, any one of which will return the same answer:

-- your calculator

-- your pencil

-- your brain

7 0

3 years ago

Read 2 more answers

The units pf the digits of a two digits numeral is 8 if the digits are reversed the new number is 18 greater than the oringal nu

ra1l [238]

complete question:

The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?

Answer:

The original number is 10a + b = 10 × 3 + 5 = 35

Step-by-step explanation:

Let

the number = ab

a occupies the tens place while b occupies the unit place. Therefore,

10a + b

The sum of the digits of two-digits numeral

a + b = 8..........(i)

If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.

Therefore,

10b + a = 18 + 10a + b

10b - b + a - 10a = 18

9b - 9a = 18

divide both sides by 9

b - a = 2...............(ii)

a + b = 8..........(i)

b - a = 2...............(ii)

b = 2 + a from equation (ii)

Insert the value of b in equation (i)

a + (2 + a) = 8

2a + 2 = 8

2a = 6

a = 6/2

a = 3

Insert the value of a in equation(ii)

b - 3 = 2

b = 2 + 3

b = 5

The original number is 10a + b = 10 × 3 + 5 = 35

6 0

3 years ago

Sarah kept track of the points she scored during her first five basketball games in the table shown. easy help

AURORKA [14]

Answer:

E

Step-by-step explanation:

If you add 22 onto the sum of all the points and divide by the amount of games (6), you get 12.

8 0

2 years ago

The mean of a population is 74 and the standard deviation is 15. The shape of the population is unknown. Determine the probabili

Lena [83]

Answer:

a) 0.0548 = 5.48% probability of a random sample of size 36 yielding a sample mean of 78 or more.

b) 0.9858 = 98.58% probability of a random sample of size 150 yielding a sample mean of between 71 and 77.

c) 0.5793 = 57.93% probability of a random sample of size 219 yielding a sample mean of less than 74.2

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .