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2 years ago

A rabbit runs 35 feet in 7 seconds, a cat runs 18 feet in 2 seconds. Who is faster?

Mathematics

1 answer:

barxatty [35]2 years ago

3 0

Answer:

The cat is faster.

Step-by-step explanation:

Compare the animals' speeds in feet per second.

Rabbit:

feet/sec = 35/7

= 5ft/sec

Cat:

feet/sec = 18/2

= 9 ft/sec

9 ft/sec is faster than 5ft/sec.

The cat is faster.

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2 years ago

What is the completely factored form of of this polynomial 81x^4 - 16y^4

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3 years ago

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3 years ago

What is the sum of the sequence 152,138,124, ... if there are 24 terms?

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Step-by-step explanation:

To solve the exercise you must use the formula shown below:

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You should find $a_{24}$

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3 years ago

Read 2 more answers

A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a

zavuch27 [327]

Answer:

$Area = 3\dfrac{15}{16}\ sq\ ft$

Area is greater than $3\frac{1}{2}$ sq ft.

Step-by-step explanation:

Length of rectangular sign board = $3\frac{1}{2}$ ft

Width of rectangular sign board = $1\frac{1}{8}$ ft

Area of a rectangle is given by the formula:

$A = Length \times Width$

To find the area, we are going to multiply $3\frac{1}{2}$ with $1\frac{1}{8}$ .

$1\frac{1}{8}$ is greater than 1.

Therefore the multiplication will be greater than $3\frac{1}{2}$ .

Hence, we can say that area will be greater than $3\frac{1}{2}$ sq ft.

Area of the sign:

$A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft$

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2 years ago