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3 years ago

How to write 899,501 in expanded form

Mathematics

2 answers:

adell [148]3 years ago

5 0

800,000+90,000+9,000+500+1

Katena32 [7]3 years ago

4 0

8*100,000+9*10,000+9*1,000+5*100+0*10+1*1

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80ptss!!! Consider the following expressions shown below.

Step2247 [10]

The first one is A the second is C and the third is B

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3 years ago

The green arcs show a pair of SAME SIDE INTERIOR ANGLES.

kramer

It would be purple and green

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3 years ago

Calculus question plzzzz

miss Akunina [59]

Answer:

Step-by-step explanation:

$f(x)=\frac{1}{\sqrt{x} }\\f'(x)=-\frac{1}{2} x^{-\frac{3}{2}}\\\\f'(4)=-\frac{1}{2} 4^{-\frac{3}{2} }=-\frac{1}{2} \frac{1}{4^\frac{3}{2} } \\=-\frac{1}{2} *\frac{1}{8}=-\frac{1}{16} \\when x=4\\y=f(x)=\frac{1}{\sqrt{4} } =\frac{1}{2} \\\\eq.~ of ~tangent ~line~is\\y=-\frac{1}{2} -\frac{1}{16} (x-4)$

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3 years ago

(with steps please) Find the inverse Laplace transform, f(t), of the function: 16/(s-4)^3

Stells [14]

Answer: The required inverse transform of the given function is

$f(t)=8t^2e^{4t}.$

Step-by-step explanation: We are given to find the inverse Laplace transform, f(t), of the following function :

$F(s)=\dfrac{16}{(s-4)^3}.$

We have the following Laplace formula :

$L\{t^ne^{at}\}=\dfrac{n!}{(s-a)^{n+1}}\\\\\\\Rightarrow L^{-1}\{\dfrac{1}{(s-a)^{n+1}}\}=\dfrac{t^ne^{at}}{n!}.$

Therefore, we get

$f(t)\\\\=L^{-1}\{\dfrac{16}{(s-4)^3}\}\\\\\\=16\times\dfrac{t^{3-1e^{4t}}}{(3-1)!}\\\\\\=\dfrac{16}{2}t^2e^{4t}\\\\\\=8t^2e^{4t}.$

Thus, the required inverse transform of the given function is

$f(t)=8t^2e^{4t}.$

6 0

3 years ago

A swimming pool at a park measures 9.75 meters by 7.2 meters the area of the playground is one and half times that of the swimmi

ElenaW [278]

9.75 x 7.2 = 70.2
Swimming Pool Area: 70.2
The Park Area: 70.2 x 1.5 = 105.3
Total Area of both Swimming Pool & Park area: 70.2 + 105.3 = 175.5
Final Answer: 175.5

8 0

3 years ago