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ankoles [38]
3 years ago
11

An egg of a certain kind of insect called a Tachinidae is 0.00002 meters long. What is this length in scientific notation?

Mathematics
2 answers:
GaryK [48]3 years ago
6 0
2.0x10^-5 or 2.0E-5 —this is because as a small decimal number, you move the decimal to the right five spaces and then add a negative to the decimal to indicate that when you translate back (from scientific notation to 0.00002) you will move the decimal to the left
Alex3 years ago
5 0

Answer:

2\times10^{-5}.

Step-by-step explanation:

We have been given that an egg of a certain kind of insect called a Tachinidae is 0.00002 meters long. We are asked to write the length in scientific notation.

To write a number in scientific, we need to factors. One factor is between 0 and 10 and second is a power of 10.

The first factor will be 2.

Since our given number has 5 digits after decimal, so we will multiply 2 by 1 divided by 10 to the fifth power.

0.00002=2\times\frac{1}{10^5}

Using exponent property \frac{1}{a^m}=a^{-m}, we can write our expression as:

0.00002=2\times10^{-5}

Therefore, the length in scientific notation would be 2\times10^{-5}.

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Answer:

  R''(2, 1), S''(-1, 7), T''(2, 7)

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Rotation 90° CCW is accomplished by the transformation ...

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Translation 3 left and 8 up is accomplished by the transformation ...

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Together, the two transformations give ...

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So your transformed points are ...

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3 years ago
Darius counted that he walks 864 steps from his house to the bookstore. If Darius takes 52 steps each minute, about how long wil
MakcuM [25]

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It would take him approximately 16.62 minutes to reach the bookstore

Step-by-step explanation:

Total steps to the bookstore=Number of steps per minute×number of minutes

where;

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Replacing;

864=52×t

t=864/52

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Reduce this algebraic fraction. y^3 -3y^2+y-3 / y^2-9
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y³ - 3y² + 1/y+3

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With Obesity on the rise, a Doctor wants to see if there is a linear relationship between the Age and Weight and estimating a pe
Romashka [77]

Answer:

112.569 ( D )

Step-by-step explanation:

Applying the estimated Regression Equation

y = b1X1 + b2X2 + a

b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884

b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925

a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252

y = 0.939X1 + 0.309X2 + 31.733

For x1 ( age ) =39, and  x2(weight) =143

y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569

where

Sum of X1 = 981

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Sum of Y = 2388

Mean X1 = 61.3125

Mean X2 = 193.875

Mean Y = 149.25

attached is the Tabular calculation of the required values needed for estimated regression equation

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