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2 years ago

Which of the following expressions can be used to calculate the area of a square with side lengths 5 inches?

Mathematics

1 answer:

NemiM [27]2 years ago

4 0

Step-by-step explanation:

5x5

because 5^2 equals the area

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Find an ordered pair (x y) that is a solution to the equation calculator

galina1969 [7]

Pick a value for 'x' then solve for the 'y'

Ex: X=6 then 6-2y=2 then 4=2y then y=2y

So your answer will be 6,2.

Another answer to your question would be 4,1.

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3 years ago

A bag has 4 red marbles, 5 blue marbles, and 6 green marbles. What is the probability if choosing a red marble from the bag, not

noname [10]

Step-by-step explanation:

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mark brainlist!!!

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2 years ago

I’ll mark brainlest

galina1969 [7]

Answer: blank number 1 would be 4, and blank number 2 would be 8. then, blank number 3 would be 3. blank number 4 would be 2,048.

Explaination:

the starting number of employees is 4, so that starts off as our base number in the first blank. we are multiplying the 4 by how many will be there in 8 years, so that's why it goes in the second blank. now, we are tripling this every year, so that goes in the 3rd blank as the exponent. multiply all that together in a calculator, and you get 2,048.

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3 years ago

Explain why sin^-1(sin(3pi/4))does not equal 3pi/4 when y=sin x and y=sin^-1 x are inverses.

Fofino [41]

Because they're not inverses, not exactly. $\sin x$ is not invertible on its entire domain because it's not one-to-one. There are infinitely many values of $x$ such that $\sin x=0$ , for example.

The standard function $\sin^{-1}x$ has a domain of $-1\le x\le1$ and outputs values between $-\dfrac\pi2$ and $\dfrac\pi2$ . This means that its inverse, $\sin x$ , is indeed its inverse as long as $-\dfrac\pi2\le x\le\dfrac\pi2$ .

$\dfrac{3\pi}4$ is larger than $\dfrac\pi2$ and thus does not fall in the "invertible part" of the domain of $\sin x$ . We have

$\sin\dfrac{3\pi}4=\dfrac1{\sqrt2}$

which is a value between -1 and 1, so that

$\sin^{-1}\left(\sin\dfrac{3\pi}4\right)=\sin^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4$

If we wanted to recover $\dfrac{3\pi}4$ , we'd have to redefine $\sin^{-1}x$ or define a new inverse function that works on a different branch of the domain of $\sin x$ .

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3 years ago

What is the side length of the picture after it has been successively scaled by 60% 4 times? Round your answer to the nearest te

eimsori [14]

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2 years ago