First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
We need to find a common denominator(bottom number of fraction)
5/3 = 25/15 (multiply both top and bottom by 5)
1/5 = 3/15 (multiply both top and bottom by 3)
Now since the denominator is the same we can add to get 25/15 + 3/15 = 28/15
So you multiply the 4th power
2 times 4 is 8
4 times 3 is 12
Then you plug it In 8x^12
So your answer is D
Hope this helps *smiles*
To answer, it is assumed that e here is the Euler number which is equal to 2.718. Substitute this value to the e of the second equation to get the value of b.
b = 0.5(2.718^2) = 3.6945
Then, we substitute this value to the first equation to get the value of a.
a = 4(3.6945^2) = 54.498
Thus, the answer is approximately equal to 54.5.
