All categories

3 years ago

Item 4 Evaluate. 6^2+(3⋅4)− 2^4

Mathematics

2 answers:

ELEN [110]3 years ago

7 0

Answer: 32

Step-by-step explanation: 6 to the power of 2 is 36 plus 12 because 4 times 3 is 12 and minus 16

so 36+12-16= 32

jok3333 [9.3K]3 years ago

6 0

32 do pemdas that’s how i learned

You might be interested in

analyze the diagram below and complete the instructions that follow . find the value of z. A.11 B.32 C.50 D.68

masha68 [24]

Answer:

Step-by-step explanation:

x = √30² - 18² = √576 = 24

tan A = 18/24 = 3/4

∠A = ∠B

tan B = tan A = 24 / y = 3 / 4

y = (24 x 4) / 3 = 32

Z = y + 18 = 32 + 18 = 50

3 0

3 years ago

Why does it work to multiply the divisor and the dividend by the same power of ten (such as 10, 100, 1000) and you still get the

alisha [4.7K]

Pretty sure it’s 28 try that

3 0

2 years ago

What is the value of y? 39 34 16 20 one of those number is the answer

melomori [17]

Answer:

Step-by-step explanation:

we see here that angle RPN is 180 degrees. SPM is 90 degrees so

angle RPS + angle SPM + angle MPN = 180 degrees

(4y - 10) + 90 + y = 180

(4y - 10) + y = 90

5y - 10 = 90

5y = 100

y = 20

5 0

3 years ago

What is the y intercept of (-6, -5) when the slope is -2/3?

Alecsey [184]

X must be increased by 6 to get its value to be 0. Then the corresponding change in y will be (-2/3)*6 = -4. That value added to -5 makes it -9.

The y-intercept will be -9.

6 0

3 years ago

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t

motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

$99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = 15.5$

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = 0.4957$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where $\bar{x}$ is the sample mean and Margin of error is given by

$$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample size, s is the sample standard deviation and is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

$MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\$

So the required 99% confidence interval is

$\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0

3 years ago