Okay I’ll try!!!!! Let me go check it out
The first thing you should do is solve the equation yourself.
1) Distribute the 2.
6x + 4 = 2x – 16
2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16
3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
4x = -12
4) Finally, divide both sides by 4
4x/4 = -12/4
x = –3
To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.
Answer:
I believe your have to find the linear lines in order to find the answer.
Step-by-step explanation:
Answer:
( -4, -3 )
Step-by-step explanation:
Let's solve by elimination. Reason being there are no variables without coefficients.
−5y+3x=3 Multiply equation by 3. Each term.
−8y+9x=−12
-15y + 9x = 9 Subtract the to equations
-8y + 9x = -12
___________
-7y = 21
y = -3
Substitute y into original equation
-5(-3) + 3x = 3
15 + 3x = 3 Subtract 15 both sides
3x = -12 Divide by 3, both sides
x = -4
Quotient : 5x + 8 Remainder : 14x2 + 5x + 11