Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
try 6 i think
Step-by-step explanation:
Answer with Step-by-step explanation:
We are given an expression:
28 + x - 2n + 7 - n - 5x + 4
We have to find its equivalent expression
On combining the like terms of the above expression
28+4+7+x-5x-2n-n
= 39-4x-3n
= -3n-4x+39
According to Tyrone the equivalent expression was:
-3n - 5x + 39 + x
The error Tyrone made was:
A. Tyrone neglected to combine the x terms
Answer:
The solution is in the attached file
It would be the absolute value of -74 - 48. so the answer is 28.
