Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.
Since, perimeter is the total length of the outer boundary of the figure. Therefore,
Perimeter of the polygon is


Area of the polygon = Area of Rectangle + Area of Triangle
![=[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]](https://tex.z-dn.net/?f=%3D%5B%2818%29%20%5Ctimes%20%2815%29%5D%20%2B%20%5B%28%5Cfrac%7B1%7D%7B2%7D%29%20%5Ctimes%20%288%29%20%5Ctimes%20%2815%29%5D)
![=270 + [(\frac{8}{2}) \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B%28%5Cfrac%7B8%7D%7B2%7D%29%20%5Ctimes%20%2815%29%5D)
![=270 + [4 \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B4%20%5Ctimes%20%2815%29%5D)


Translation.
The flat only shifts upwards or downwards, and it doesn’t turn around.
Answer: The area of the Polygon D is 36 times larger than the area of the Polygon C.
Step-by-step explanation:
<h3>
The complete exercise is: "Polygon D is a scaled copy of Polygon C using a scale factor of 6. How many times larger is the area of Polygon D than the area Polygon C"?</h3>
In order to solve this problem it is important to analize the information provided in the exercise.
You know that the Polygon D was obtained by multiplying the lengths of the Polygon C by the scale factor of 6.
Then, you can identify that the Length scale factor used is:

Now you have to find the Area scale factor.
Knowing that the Length scale factos is 6, you can say that the Area scale factor is:

Finally, evaluating, you get that this is:

Therefore, knowing the Area scale factor, you can determine that the area of the Polygon D is 36 times larger than the area of the Polygon C.
You add all the sides together for perimeter