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solniwko [45]
4 years ago
12

Which value of x makes 7+5 (x-3)=22 a true statement

Mathematics
2 answers:
attashe74 [19]4 years ago
7 0

Answer:

x = 6

Step-by-step explanation:

7 + 5(x - 3) = 22

First, distribute the 5 on the left side.

7 + 5x - 15 = 22

Now, combine like terms on the left side.

5x - 8 = 22

Add 8 to both sides.

5x = 30

Divide both sides by 5.

x = 6

slavikrds [6]4 years ago
6 0

Answer:

x=6

Step-by-step explanation:

7+5 (x-3)=22

Subtract 7 from each side

7-7+5 (x-3)=22-7

5(x-3) = 15

Divide each side by 5

5(x-3)/5 = 15/5

x-3 = 3

Add 3 to each side

x-3+3=3+3

x=6

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Pilates is a popular set of exercises for the treatment of individuals with lower back pain. The method has six basic principles
Bas_tet [7]

Answer:

a) We reject H₀     We find difference between the mean of the two groups

b) we accept H₀ : There is no statistical difference  ( in the scale of pain) when the difference in samples means is 1

Step-by-step explanation:

Group 1: Only with educational material

Sample size     n₁  =  42

Sample mean   x₁  =  3,2

Sample standard deviation  s₁  =  2,3

Group 2: With exercises with the treatment of individuals

Sample size    n₂   =  42

Sample mean    x₂  = 5,2  

Sample standard deviation   s₂  = 2,3

Test Hypothesis

Null Hypothesis                     H₀           x₂  -  x₁  = 0  or    x₁  =  x₂

Alternative Hypothesis         Hₐ           x₂  -  x ₁ > 0  or    x₂  >  x₁

Significance level  α  = 0,01

Sample sizes are n₁  =  n₂  >  30

We use z-test

for α  = 0,01     z(c)  ≈  2,32

To calculate z(s)

z(s)  =  (  x₂  -  x₁ ) / √ (2,3)²/42  + (2,3)²/42

z(s)  = ( 5,2  -  3,2 )/ √0,2519

z(s)  =  2 / 0,5

z(s) = 4

Comparing  z(s)  and z(c)

z(s) > z(c)

z(s) is in the rejection region. We reject H₀ the true average pain level for the control condition exceeds that for the treatment condition.

b) Does the true average pain level for the control condition exceed that for the treatment condition by more than 1.

In this case

z( s) =  x₂ - x₁ / 0,5

z(s) =  1 /0,5

z(s) = 2

Comparing z(s) and z(c)  now

z(s) < z(c)        2 < 2,32

And z(s) is in the acceptance region ( for the same significance level) and we should accept H₀  equivalent to say that the two groups statistical have the same mean

5 0
3 years ago
Write the equation for the parabola that has x− intercepts (−2,0) and (1.2,0) and y− intercept (0,−4).
schepotkina [342]

Answer: The answer is 15y+4=25(x-1.6)^2.


Step-by-step explanation:  We are to find the equation of the parabola with x-intercepts (-2,0), (1.2,0) and y-intercept (0,-4).

Therefore, axis of symmetry is

x=\dfrac{1.2+2}{2}\\\\\Rightarrow x=1.6.

Let the equation of the parabola be y=a(x-1.6)^2+k.

Substituting the points (x,y)=(0,-4) and (1.2,0) in the above equation, we find that

-4=a(0-1.6)^2+k\\\\\Rightarrow k=-2.56a-4

and

0=a(1.2-1.6)^2+k\\\\\Rightarrow k=-0.16a.

Solving the above two equations, we get

a=-\dfrac{5}{3}~~\textup{and}~~k=-\dfrac{4}{15}.

So, putting the values of 'a' and 'k' in the equation of the parabola, we get

y=-\dfrac{5}{3}(x-1.6)^2-\dfrac{4}{15}\\\\\Rightarrow 15y+4=-25(x-1.6)^2.

Thus, the equation of the parabola is  15y+4=25(x-1.6)^2.


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Answer:

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