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Rus_ich [418]
2 years ago
8

Please help me asap

Mathematics
1 answer:
sergeinik [125]2 years ago
8 0

Answer:

C

Step-by-step explanation:

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HELP ME ASAP.
slavikrds [6]

Answer:

The first number lets say is x

the second is y so

y=1/2x+8

x+1/2x+8=58

1 1/2x=50

x= 33 1/3

Hope This Helps!!!

6 0
3 years ago
Read 2 more answers
A plumber charges $52.50 per hour plus a $75.00 service charge. Your father's firm hired him to fix some leaky pipes.
Setler79 [48]
Cost as a function of hours is:

c(h)=52.5h+75
4 0
3 years ago
If f(x)=5(x-3)+4 what is the value of f(2)?
algol13

Answer:

-1

Step-by-step explanation:

6 0
3 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
I'LL A LOT OF POINT'S
Over [174]
Exponential :))))))))))))))))
3 0
3 years ago
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