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2 years ago

Find the coordinates of the midpoint of LB if L(8,5) and B(-6,2) 10 points!!!

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

3 0

Answer:

A, (1, 3+1/2)

Step-by-step explanation:

Midpoint formula for reference: m= {(x1 + x2)/2, (y1 + y2)/2}

Plugging in the points we get: m= {(8 - 6)/2, (5 + 2)/2}

Now we simplify using PEMDAS. First step is parentheses.

m= {2/2, 7/2}

Simplifying again (and making 7/2 a mixed number), it becomes

m= {1, 3+1/2}

Hope this helps!

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One of my students got 95, 98, and 32 for the two Principal tests and for the final test. a What is the average of her three tes

kobusy [5.1K]

Answer:

Her average is 75

Step-by-step explanation:

To be able to find the average of a group of numbers you must add them all then divide them by how many numbers that there are.

Step 1: Add all the values

$95+98+32= 225$

Step 2: Divide

$\frac{225}{3} =75$

Step 3: Check your work

$75*3 =225$

Step 4: Celebrate

You got the correct answer, now be proud of yourself.

5 0

2 years ago

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A blueberry pie is shot out of a pie cannon from a height of 6m and with a velocity of 60 m/s. How many seconds will pass before

sveta [45]

Answer: 1.106 s

Step-by-step explanation:

This situation is related to projectile motion and one the equation that models the height of the blueberry pie in time is:

$y=y_{o}+V_{o}sin(\theta) t-\frac{1}{2}gt^{2}$

Where:

$y=0 m$ is the blueberry pie final height (when it hits the ground)

$y_{o}=6 m$ is the blueberry pie initial height

$V_{o}=60 m/s$ is the blueberry pie initial velocity

$\theta=0 \°$ is the angle, assuming the pie was shot horizontally

$t$ is the time

$g=9.8 m/s^{2}$ is the acceleration due gravity

Rewriting the equation:

$0=y_{o}-\frac{1}{2}gt^{2}$

Isolating $t$ :

$t=\sqrt{\frac{2y_{o}}{g}}$

$t=\sqrt{\frac{2(6 m)}{9.8 m/s^{2}}}$

Finally:

$t=1.106 s$

5 0

3 years ago

Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

7 0

2 years ago

2 mi. yd. I'm confused

dybincka [34]

Answer && Step-by-step explanation:

Obtain yards by multiplying miles by 1760

== 3520 yards

6 0

3 years ago

Abby's friend told her that he drew a quadrilateral with exactly one pair of parallel sides. Abby said it must be a trapezoid. I

Ratling [72]

Answer:

Yes, she is correct

Step-by-step explanation:

A trapezoid has exactly one pair of parallel lines and 4 sides

8 0

2 years ago

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